0=-16x^2+80x+6

Solution for 0=-16x^2+80x+6 equation:

0=-16x^2+80x+6

We move all terms to the left:

0-(-16x^2+80x+6)=0

We add all the numbers together, and all the variables

-(-16x^2+80x+6)=0

We get rid of parentheses

16x^2-80x-6=0

a = 16; b = -80; c = -6;
Δ = b2-4ac
Δ = -802-4·16·(-6)
Δ = 6784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6784}=\sqrt{64*106}=\sqrt{64}*\sqrt{106}=8\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-8\sqrt{106}}{2*16}=\frac{80-8\sqrt{106}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+8\sqrt{106}}{2*16}=\frac{80+8\sqrt{106}}{32}
$